Poprawnych odpowiedzi jest kilka.
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const numbers = [5, 3, 4, 22, 5, 51, 2, 4]; function evenNumbers (p_array) { return p_array.filter((x => (x % 2) == 1)); } console.log(evenNumbers(numbers));
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const numbers = [5, 3, 4, 22, 5, 51, 2, 4]; function evenNumbers (p_array) { let temp_array = []; for (let x of p_array) { if (x % 2 != 1) temp_array.push(x); } console.log(temp_array); } evenNumbers(numbers);
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const numbers = [5, 3, 4, 22, 5, 51, 2, 4]; function evenNumbers (p_array) { return p_array.filter((x => (x % 2) == 0)); } console.log(evenNumbers(numbers));
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const numbers = [5, 3, 4, 22, 5, 51, 2, 4]; function evenNumbers (p_array) { let temp_array = []; for (let i = 0; i < p_array.length; i++) { if (p_array[i] % 2 == 0) temp_array.push(p_array[i]); } document.write(temp_array); } evenNumbers(numbers);